2sin^2x-7cosx=5

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Solution for 2sin^2x-7cosx=5 equation:


Simplifying
2sin2x + -7cosx = 5

Reorder the terms:
-7cosx + 2in2sx = 5

Solving
-7cosx + 2in2sx = 5

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2in2sx' to each side of the equation.
-7cosx + 2in2sx + -2in2sx = 5 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
-7cosx + 0 = 5 + -2in2sx
-7cosx = 5 + -2in2sx

Divide each side by '-7osx'.
c = -0.7142857143o-1s-1x-1 + 0.2857142857in2o-1

Simplifying
c = -0.7142857143o-1s-1x-1 + 0.2857142857in2o-1

Reorder the terms:
c = 0.2857142857in2o-1 + -0.7142857143o-1s-1x-1

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